வார்ப்புரு:Uw-copyright-link
When adding links to material on external sites, please ensure that the external site is not violating the creator's copyright. Linking to websites that display copyrighted works is acceptable as long as the website's operator has created or licensed the work. Knowingly directing others to a site that violates copyright may be considered contributory infringement. This is particularly relevant when linking to sites such as யூடியூப், where due care should be taken to avoid linking to material that violates its creator's copyright. Wikipedia takes copyright violations very seriously, and persistent violators will be blocked from editing.
Template documentation
இந்த வார்ப்புருவானது எப்போதும் பதிலிடப்படவேண்டும். அதாவது, {{subst:Uw-copyright-link}}. தவறுதலான உள்ளீடுகள் பதிலிடப்படும். |
If you plan to make breaking changes to this template, move it, or nominate it for deletion, please notify Twinkle's users and maintainers at Wikipedia talk:Twinkle as a courtesy, as this template is used in the standard installation of Twinkle. Thank you! |
Usage:
{{subst:Uw-copyright-link}}
{{subst:Uw-copyright-link|Article}}
references a specific article{{subst:Uw-copyright-link|Article|Additional text}}
adds text onto the end of the message
- This standardized template conforms to guidelines by the user warnings project. You may discuss the visual appearance of these standardized templates (e.g. the image in the top-left corner) at the user warning talk page.
- Please refer to the index of message templates before using any template on user talk pages to warn a user. Applying the best template available for your purpose may help reduce confusion from the message you are sending.
- Please remember to substitute the template using
{{subst:Uw-copyright-link}}
rather than{{Uw-copyright-link}}
. - To give greater detail to your message, you may add the article and some additional text to the end of the template. If such article or additional text includes a URL or anything which includes an equal sign ("="), it may break the parser's function unless you prefix the article or the text with a named template parameter. Use "
1=
" if the article contains an equals sign and use "2=
" if the additional text contains an equals sign (such as a URL).